 | John Playfair - 1806 - 320 páginas
...AB.BH is equal to the square of AH. Which was to be done, Book II. PROP. XII. THEOR. IN obtuse angled triangles if a perpendicular be drawn from either...produced, the square of the side subtending the obtuse aigle is greater than the squares of the sides contain ng the obtuse angle, by twice the rectangle... | |
 | Charles Hutton - 1811 - 406 páginas
...And AC + BC . AC — BC = AB.AD + BD in the 1st figure. THEOREM XXXVI. IN any Obtuse-angled Triangle, the Square of the Side subtending the Obtuse Angle, is Greater than the Sum of the Squares of the other two Sides, by Twice the Rectangle of the Base and the Distance of the... | |
 | Charles Hutton - 1812 - 620 páginas
...And AC+BC . AC — BC =AB . AD + BD in the 1st figure. THEOREM XXXVI. IN any Obtuse-angled Triangle, the Square of the Side subtending the Obtuse Angle, is Greater than the Sum of the Squares of the other two Sides, by Twice the Rectangle of the Base and the Distance of the... | |
 | John Mason Good - 1813 - 714 páginas
...the other part. Prop. XII. Theor. In obtuse angled triangles, if a perpendicular be drawn from any of the acute angles to the opposite side produced,...square of the side subtending the obtuse angle is greatcf than the squares of the sides containing the obtuse angle, by twice the rectangle contained... | |
 | John Mason Good - 1819 - 800 páginas
...the other part. Prop. XII. Theor. In obtuse angled triangles, if a perpendicular be drawn from any of the acute angles to the opposite side produced, the square of the side subtending the obtuse anule it greatt-i than the squares of the sides containing the obtuse angle, by twice the rectangle... | |
 | Charles Hutton - 1822 - 616 páginas
...+ BC . AC — BC = AB . AB -f- BB in the 1st figure. THEOREM XXXVI. IN any Obtuse-angled Triangle, the Square of the Side subtending the Obtuse Angle, is Greater than the Sum of the Squares of the other two Sides, by Twice the Rectangle of the Base and the Distance of the... | |
 | Euclides - 1826 - 226 páginas
...equal to the square of AH. Which was to be done. PROPOSITION XII. THEOREM. In obtuse angled triangles, the square of the side subtending the obtuse angle is greater than the squares, which are made by the sides containing the obtuse angle by twice the rectangle contained under one... | |
 | John Playfair - 1829 - 210 páginas
...in all respects. In any obtuse-angled triangle, if a perpendicular be drawn from either of the two acute angles to the opposite side produced, the square...side subtending the obtuse angle is greater than the sum of the squares of the sides containing it by twice the rectangle under the base and the distance... | |
 | John Playfair - 1832 - 358 páginas
...was to be done. B PROP. XII. THEOR. In obtuse angled triangles, if a perpendicular be drawn from any of the acute angles to the opposite side produced,...subtending the obtuse angle is greater than the squares of I he sides containing the obtuse angle, by twice Ihe reel angle contained by the side upon which, when... | |
 | John Playfair - 1833 - 346 páginas
...was to be done. PROP. XII. THEOR. In obtuse angled triangles, if a perpendicular be drawn from any of the acute angles to the opposite side produced,...of the sides containing the obtuse angle, by twice therectangle contained by tfie side upon which, when produced, the perpendicular falls, and the straight... | |
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In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square on the side subtending the obtuse angle, is greater than the squares on the sides containing the obtuse angle, by twice the... 
