Imagens das páginas
PDF
ePub

Examples of putting Questions into Equations.

where likewise he spent 2 shillings, and borrowed as much as he had left; and again spending 2 shillings at a fourth tavern, he then had nothing remaining. What had he at first?

Ans. If x= the shillings he had at first,

the required equation is

[merged small][ocr errors]

13. A person possessed a certain capital, which he placed out at a certain interest. Another person, who possessed $10 000 more than the first, and who put out his capital 1 per cent. more advantageously than the first did, had an income greater by $800. A third person, who possessed $ 15 000 more than the first, and who put out his capital 2 per cent, more advantageously than the first, had an income greater by $1500. Required the capitals of the three persons, and the three rates of interest.

Ans. If x= the capital of the first,

y= his rate of interest per cent.

[blocks in formation]

14. A person has three kinds of goods, which together cost $2305. The pound of each article costs as many twenty-fourths of a dollar as there are pounds of that article; but he has one third more of the second kind than he has of the first, and 3 times as much of the third as he has of the second. How many pounds has he of each article? Ans. If x= the number of pounds of the first,

the required equation is

zx2+z2x2+‡‡ x2=230,4.

Examples of putting Questions into Equations.

15. A person buys some pieces of cloth, at equal prices, for $60. Had he got 3 pieces more for the same sum, each piece would have cost him $1 less. How many pieces did he buy?

[blocks in formation]

16. Two drapers A and B cut, each of them, a certain number of yards from a piece of cloth; A however 3 yards less than B, and jointly receive for them $35. "At my own price," said A to B, “I should have received $24 for your cloth." "I must admit," answered the other, "that, at my low price, I should have received for your cloth no more than $ 124." How many yards did each sell?

Solution.

then

Let x = the number of yards sold by A;
x+3:

=

the number sold by B.

Now since A would have sold x + 3 yards for $24,

[blocks in formation]

and since B would have sold x yards for $124,

[merged small][merged small][merged small][merged small][merged small][ocr errors][ocr errors][merged small][merged small]

the sum for which B sells x + 3 yards

and the required equation is

24 x x+3

=

24 x

x+3'

[blocks in formation]
[blocks in formation]

Examples of putting Questions into Equations.

17. Two travellers, A and B, set out at the same time from two different places, C and D; A, from C to D; and B, from D to C. When they met, it appeared that A had already gone 30 miles more than B; and, according to the rate at which they are travelling, A calculates that he can reach the place D in 4 days, and that B can arrive at the place C in 9 days. What is the distance between C and D ? Ans. If, when they meet,

then,

x = the distance gone by A, z-30 the distance gone by B;

the whole distance = 2x-30;

and the required equation is

[merged small][ocr errors][merged small][ocr errors][ocr errors]

18. Some merchants jointly form a certain capital, in such a way that each contributes 10 times as many dollars as they are in number; they trade with this capital, and gain as many dollars per cent, as exceed their number by 8. Their profit amounts to $288. How many were there of them?

Ans. If x = the number of merchants, the required equation is

To x2 (x+8)=288.

19. Part of the property of a merchant is invested at such a rate of compound interest, that it doubles in a number of years equal to twice the rate per cent. What is the rate

of interest?

Ans. If x the rate per cent., the required equation is

[blocks in formation]

Degree of an Equation.

SECTION II.

Reduction and Classification of Equations.

104. The portions of an equation, which are separated by the sign, are called its members; the one at the left of the sign being called its first member, and the other its second member.

105. Equations are divided into classes according to the form in which the unknown quantities are contained in them. But before deciding to which class an equation belongs, it should be freed from fractions, from negative exponents, and from the radical signs which affect its unknown quantities; its members should, if possible, be reduced to a series of monomials, and the polynomials thus obtained should be reduced to their simplest forms.

106. When the equation is thus reduced, it is said. to be of the same degree as the number of dimensions of the unknown quantities in that term which contains the greater number of dimensions of the unknown quantities.

Thus, x and y being the unknown quantities, the equations

ax + b = c,

10x + y = 3,

are of the first degree;

x2+3x+1 = 5,

xy=11,

are of the second degree, &c.

Transcendental Equations; Roots of Equations.

107. But when an equation does not admit of being reduced to a series of monomials, or, when being so reduced, it contains terms in which the unknown quantities or their powers enter otherwise than as factors, it is said to be transcendental; and the consideration of such equations belongs to the higher branches of mathematics.

Thus,

a=b

(x + a) y + b = c,

are transcendental equations.

108. An equation is said to be solved, when the values of its unknown quantities are obtained; and these values are called the roots of the equation.

109. The reduction and solution of all equations depends upon the self-evident proposition, that

Both members of an equation may be increased, diminished, multiplied, or divided by the same quantity, without destroying the equality.`

110. Corollary. If all the terms of an equation have a common factor, this factor may be suppressed.

111. EXAMPLES.

1. If the factor common to the terms of the equation

a2 x5 + 3 a3 x2 = a2 x2 |

a* z° + 3 @° ° = ༔

is suppressed, what is the resulting equation?

[blocks in formation]

2. If the factor common to the terms of the equation a* + 3 a* +1 x = a* − 1

is suppressed, what is the resulting equation?

Ans. a +3 a2 x = 1.

« AnteriorContinuar »